2013 AMC 10B Problem 5

Attempt Problem 5 of the 2013 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

Positive integers aa and bb are each less than 6.6. What is the smallest possible value of the following expression? 2⋅a−a⋅b2 \cdot a - a \cdot b
−20 -20
−15 -15
−10 -10
0 0
2 2
Answer: B
Concepts:factoringoptimization
Small hint:
Factor the expression as a(2−b)a(2-b)
Big hint:
Make 2−b2-b as negative as possible while making aa large
Solution:
The expression is 2a−ab=a(2−b)2a-ab=a(2-b).
To make it as small as possible, choose bb as large as possible so that 2−b2-b is most negative, and choose aa as large as possible. Since a,b<6a,b<6, take a=b=5a=b=5.
The minimum value is 5(2−5)=−155(2-5)=-15.
Thus, the correct answer is B .
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