2013 AMC 10A Problem 17

Attempt Problem 17 of the 2013 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

Daphne is visited periodically by her three best friends: Alice, Beatrix, and Claire. Alice visits every third day, Beatrix visits every fourth day, and Claire visits every fifth day.
All three friends visited Daphne yesterday. How many days of the next 365365-day period will exactly two friends visit her?
4848
5454
6060
6666
7272
Answer: B
Concepts:least common multipleinclusion-exclusioncounting integers in a range
Small hint:
Count pairwise meeting days using least common multiples
Big hint:
Subtract the triple-meeting days from each pair count
Solution:
Pairwise visits occur every lcm⁡(3,4)=12\operatorname{lcm}(3,4)=12, lcm⁡(3,5)=15\operatorname{lcm}(3,5)=15, and lcm⁡(4,5)=20\operatorname{lcm}(4,5)=20 days.
In the next 365365 days, these pair counts are ⌊36512⌋=30\left\lfloor\frac{365}{12}\right\rfloor=30, ⌊36515⌋=24\left\lfloor\frac{365}{15}\right\rfloor=24, and ⌊36520⌋=18\left\lfloor\frac{365}{20}\right\rfloor=18.
All three visit every 6060 days, which happens ⌊36560⌋=6\left\lfloor\frac{365}{60}\right\rfloor=6 times. Subtracting those days from each pair count gives (30−6)+(24−6)(30-6)+(24-6) +(18−6)=54+(18-6)=54.
Thus, B is the correct answer.
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