2013 AMC 10A Problem 14

Attempt Problem 14 of the 2013 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

A solid cube of side length 11 is removed from each corner of a solid cube of side length 3.3. How many edges does the remaining solid have?
3636
6060
7272
8484
108108
Answer: D
Concepts:polyhedroncube geometry
Small hint:
Each corner removal creates new exposed edges
Big hint:
Count the original cube edges plus the new edges from each removed corner
Solution:
Removing the cubes does not remove any edges from the original cube. It only adds edges.
After removing each cube, we can see that 99 extra edges are added to the solid.
88 cubes are removed, which means 8⋅9=728 \cdot 9 = 72 edges are added to the original 1212 edges, for a total of 72+12=8472 + 12 = 84 edges.
Thus, D is the correct answer.
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