2012 AMC 10A Problem 10

Attempt Problem 10 of the 2012 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

Mary divides a circle into 1212 sectors. The central angles of these sectors, measured in degrees, are all integers and they form an arithmetic sequence. What is the degree measure of the smallest possible sector angle?
55
66
88
1010
1212
Answer: C
Concepts:arithmetic sequenceDiophantine Equationoptimization
Small hint:
Let the arithmetic sequence be a,a+d,…,a+11da,a+d,\ldots,a+11d
Big hint:
Use 12a+66d=36012a+66d=360 and maximize dd while keeping aa positive
Solution:
Let aa be the smallest possible sector angle and dd be the difference in the arithmetic sequence.
Then we have that 122(a+a+11d)=12a+66d \dfrac{12}{2}(a + a + 11d) = 12a + 66d is the sum of the arithmetic sequence.
We have that this sums to 360,360, so 12a+66d=360 12a + 66d = 360 2a+11d=60. 2a + 11d = 60.
We want to minimize a,a, so we maximize d.d. If d=5,d = 5, then aa is not an integer, so d=4d = 4 and a=8.a = 8.
Thus, C is the correct answer.
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