2011 AMC 10B Problem 7

Attempt Problem 7 of the 2011 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 10B solutions, or check the answer key.

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7.

The sum of two angles of a triangle is 65\frac{6}{5} of a right angle, and one of these two angles is 3030^{\circ} larger than the other. What is the degree measure of the largest angle in the triangle?

6969

7272

9090

102102

108108

Answer: B
Concepts:angle sumlinear equation
Difficulty rating: 1020
Solution:

The two angles add to 6590=108.\frac 65 \cdot 90 = 108. This makes the other angle 180108=72.180-108=72. Then, if the larger of the two angles is xx then the smaller of them is x30x-30 so their sum is 2x30=108,2x-30=108, making x=69.x=69.

This means no angle is larger than 72,72, making the largest equal to 72.72.

Thus, the correct answer is B .

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