2011 AMC 10A Problem 5

Attempt Problem 5 of the 2011 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

At an elementary school, the students in third grade, fourth grade, and fifth grade run an average of 12,12, 15,15, and 1010 minutes per day, respectively. There are twice as many third graders as fourth graders, and twice as many fourth graders as fifth graders. What is the average number of minutes run per day by these students?
1212
373\dfrac{37}{3}
887\dfrac{88}{7}
1313
1414
Answer: C
Concepts:meanratio and proportion
Small hint:
Use a 4:2:14:2:1 ratio for the numbers of third, fourth, and fifth graders
Big hint:
Compute a weighted average with weights 4,2,14,2,1
Solution:
WLOG, let there be one fifth grader. This then tells us that there are two fourth graders and four third graders.
We can do this, since we are only interested in the average, which is not impacted by the exact number of students.
The total number of minutes the students spend running is 12⋅4+15⋅2+10=88 12 \cdot 4 + 15 \cdot 2 + 10 = 88 minutes. The total number of students is 1+2+4=7.1 + 2 + 4 = 7. The average is then 887.\dfrac{88}{7}.
Thus, C is the correct answer.
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