2010 AMC 10A Problem 7

Attempt Problem 7 of the 2010 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

Crystal has a running course marked out for her daily run. She starts this run by heading due north for one mile. She then runs northeast for one mile, then southeast for one mile. The last portion of her run takes her on a straight line back to where she started. How far, in miles, is this last portion of her run?

11

2\sqrt{2}

3\sqrt{3}

22

222\sqrt{2}

Answer: C
Concepts:Pythagorean Theoremvector
Difficulty rating: 1220
Solution:

From the diagram, we see that the distance traveled is the hypotenuse of a right triangle.

One of the legs is just 11 from running due north. The other leg is 12+12=2. \sqrt{1^2 + 1^2} = \sqrt2.

The final distance is then 22+12=3. \sqrt{\sqrt2^2 + 1^2} = \sqrt3.

Thus, C is the correct answer.

← Problem 6#6
Full Exam

Problem 7 in Other Years