2010 AMC 10A Problem 10

Attempt Problem 10 of the 2010 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

Marvin had a birthday on Tuesday, May 2727 in the leap year 2008.2008. In what year will his birthday next fall on a Saturday?
20112011
20122012
20132013
20152015
20172017
Answer: E
Concepts:date and timemodular arithmetic
Small hint:
Each non-leap year shifts the weekday forward by 11
Big hint:
Since May 2727 is after leap day, leap years shift it forward by 22
Solution:
Note that on a normal year, we have that 365=52⋅7+1, 365 = 52 \cdot 7 + 1, which means that for a specific day, it moves to the day after the next year.
On a leap year, the day of the week moves forward two since there is an extra day.
Then in 2009,2009, this day falls on a Wednesday. In 2010,2010, it falls on a Thursday.
Similarly, in 2011,2011, it falls on a Friday. In 2012,2012, however, since it is a leap year, it falls on a Sunday.
Now, for the next three years, the day moves forward one. Then in 2016,2016, it moves forward two, landing on a Friday.
Finally, in 2017,2017, the day of the week is a Saturday.
Thus, E is the correct answer.
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