2009 AMC 10A Problem 13

Attempt Problem 13 of the 2009 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

Suppose that P=2mP = 2^m and Q=3n.Q = 3^n. Which of the following is equal to 12mn12^{mn} for every pair of integers (m,n)?(m, n)?
P2QP^2 Q
PnQmP^n Q^m
PnQ2mP^n Q^{2m}
P2mQnP^{2m} Q^n
P2nQmP^{2n} Q^m
Answer: E
Concepts:exponentprime factorization
Small hint:
Write 12=22⋅312 = 2^2 \cdot 3 and raise it to the power mnmn
Big hint:
Regroup 22mn⋅3mn2^{2mn} \cdot 3^{mn} using P=2mP = 2^m and Q=3nQ = 3^n
Solution:
Since 12=22⋅3,12 = 2^2 \cdot 3, 12mn=22mn⋅3mn=(2m)2n⋅(3n)m=P2nQm. \begin{aligned} 12^{mn} &= 2^{2mn} \cdot 3^{mn} \\ &= (2^m)^{2n} \cdot (3^n)^m \\ &= P^{2n} Q^m. \end{aligned}
Thus, the correct answer is E.
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