2006 AMC 10B Problem 12

Attempt Problem 12 of the 2006 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 10B solutions, or check the answer key.

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12.

The lines x=14y+ax=\tfrac14 y+a and y=14x+by=\tfrac14 x+b intersect at the point (1,2).(1,2). What is a+b?a+b?
00
34\dfrac{3}{4}
11
22
94\dfrac{9}{4}
Answer: E
Concepts:substitutionsystem of equations
Small hint:
Substitute (1,2)(1,2) into both equations
Big hint:
Add the two resulting equations to get a+ba+b directly
Solution:
Substituting (1,2)(1,2): from 1=14(2)+a1=\tfrac14(2)+a we get a=12,a=\tfrac12, and from 2=14(1)+b2=\tfrac14(1)+b we get b=74.b=\tfrac74.
Then a+b=12+74=94.a+b=\tfrac12+\tfrac74=\tfrac94.
Thus, the correct answer is E.
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