2005 AMC 10B Problem 3

Attempt Problem 3 of the 2005 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

A gallon of paint is used to paint a room. One third of the paint is used on the first day. On the second day, one third of the remaining paint is used. What fraction of the original amount of paint is available to use on the third day?
110\dfrac{1}{10}
19\dfrac{1}{9}
13\dfrac{1}{3}
49\dfrac{4}{9}
59\dfrac{5}{9}
Answer: D
Concepts:fractionratio and proportion
Small hint:
After day one, 23\dfrac23 of the paint remains
Big hint:
On day two, 13\dfrac13 of that 23\dfrac23 is used
Solution:
After the first day, 1−13=231 - \dfrac13 = \dfrac23 of the paint remains.
On the second day, 13⋅23=29\dfrac13 \cdot \dfrac23 = \dfrac29 of the original amount is used.
The fraction available on the third day is 23−29=49. \dfrac23 - \dfrac29 = \dfrac49.
Thus, D is the correct answer.
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