2005 AMC 10B Problem 13

Attempt Problem 13 of the 2005 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

How many numbers between 11 and 20052005 are integer multiples of 33 or 44 but not 12?12?
501501
668668
835835
10021002
11691169
Answer: C
Concepts:multipleinclusion-exclusioncounting integers in a range
Small hint:
Count multiples of 33 and of 44 separately, noting that multiples of 1212 are the overlap
Big hint:
From each of the 33-multiples and 44-multiples, remove the 1212-multiples
Solution:
Between 11 and 20052005 there are 668668 multiples of 3,3, 501501 multiples of 4,4, and 167167 multiples of 12.12.
Every multiple of 1212 is both a multiple of 33 and of 4,4, so removing them from each group gives (668−167)+(501−167)=835 \begin{aligned} &(668 - 167) \\ &\quad {}+ (501 - 167) = 835 \end{aligned} numbers that are multiples of 33 or 44 but not 12.12.
Thus, C is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.