2005 AMC 10A Problem 3

Attempt Problem 3 of the 2005 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The equations 2x+7=32x + 7 = 3 and bx−10=−2bx - 10 = -2 have the same solution x.x. What is the value of b?b?
−8-8
−4-4
−2-2
44
88
Answer: B
Concepts:linear equationsubstitution
Small hint:
Solve 2x+7=32x + 7 = 3 for xx first
Big hint:
Substitute that value of xx into bx−10=−2bx - 10 = -2 and solve for bb
Solution:
From 2x+7=32x + 7 = 3 we get x=−2.x = -2. Substituting, −2b−10=−2,-2b - 10 = -2, so −2b=8-2b = 8 and b=−4.b = -4.
Thus, the correct answer is B.
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