2005 AMC 10A Problem 10

Attempt Problem 10 of the 2005 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10A solutions, or check the answer key.

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10.

There are two values of aa for which the equation 4x2+ax+8x+9=04x^2 + ax + 8x + 9 = 0 has only one solution for x.x. What is the sum of those values of a?a?

16-16

8-8

00

88

2020

Answer: A
Concepts:quadraticalgebraic manipulation
Difficulty rating: 1370
Solution:

Writing the equation as 4x2+(a+8)x+9=0,4x^2 + (a+8)x + 9 = 0, there is one solution exactly when the discriminant (a+8)2144=0.(a+8)^2 - 144 = 0. Then a+8=±12,a + 8 = \pm 12, so a=4a = 4 or a=20,a = -20, and their sum is 16.-16.

Thus, the correct answer is A.

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