2003 AMC 10B Problem 19

Attempt Problem 19 of the 2003 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10B solutions, or check the answer key.

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19.

Three semicircles of radius 11 are constructed on diameter AB\overline{AB} of a semicircle of radius 2.2. The centers of the small semicircles divide AB\overline{AB} into four line segments of equal length, as shown. What is the area of the shaded region that lies within the large semicircle but outside the smaller semicircles?

π3\pi - \sqrt{3}

π2\pi - \sqrt{2}

π+22\dfrac{\pi + \sqrt{2}}{2}

π+32\dfrac{\pi + \sqrt{3}}{2}

76π32\dfrac{7}{6}\pi - \dfrac{\sqrt{3}}{2}

Answer: E
Concepts:circle areasectorequilateral trianglearea decomposition
Difficulty rating: 1630
Solution:

The large semicircle has area 12π(2)2=2π.\dfrac12 \pi (2)^2 = 2\pi.

Removing the small semicircles deletes a region equal to five congruent 6060^\circ sectors of radius 11 plus two equilateral triangles of side 1.1. Each sector has area π6\dfrac{\pi}{6} and each triangle has area 34.\dfrac{\sqrt3}{4}.

The shaded area is 2π5π6234=76π32. \begin{gathered} 2\pi - 5 \cdot \dfrac{\pi}{6} - 2 \cdot \dfrac{\sqrt3}{4} \\ = \dfrac{7}{6}\pi - \dfrac{\sqrt3}{2}. \end{gathered}

Thus, the correct answer is E.

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