2002 AMC 10A Problem 12

Attempt Problem 12 of the 2002 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 10A solutions, or check the answer key.

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12.

Mr. Earl E. Bird leaves his house for work at exactly 8:00 A.M. every morning. When he averages 4040 miles per hour, he arrives at his workplace three minutes late. When he averages 6060 miles per hour, he arrives three minutes early. At what average speed, in miles per hour, should Mr. Bird drive to arrive at his workplace precisely on time?

4545

4848

5050

5555

5858

Answer: B
Concepts:distance rate and timelinear equation
Difficulty rating: 1410
Solution:

Let tt hours be the on-time travel time. Since 33 minutes is 0.050.05 hours, 40(t+0.05)=60(t0.05).40(t+0.05)=60(t-0.05). Then 40t+2=60t3,40t+2=60t-3, so t=0.25.t=0.25.

The distance is 40(0.30)=1240(0.30)=12 miles, so the required speed is 120.25=48\dfrac{12}{0.25}=48 mph.

Thus, the correct answer is B.

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