2001 AMC 10 Problem 3

Attempt Problem 3 of the 2001 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The sum of two numbers is S.S. Suppose 33 is added to each number and then each of the resulting numbers is doubled. What is the sum of the final two numbers?

2S+32S+3

3S+23S+2

3S+63S+6

2S+62S+6

2S+122S+12

Answer: E
Concepts:algebraic manipulationdistributive property
Difficulty rating: 870
Solution:

Let the numbers be aa and b,b, so a+b=S.a+b=S. After adding 33 to each and doubling, the sum is 2(a+3)2(a+3) +2(b+3)+2(b+3) =2(a+b)+12=2(a+b)+12 =2S+12.=2S+12.

Thus, the correct answer is E.

← Problem 2#2
Full Exam

Problem 3 in Other Years