2001 AMC 10 Problem 17

Attempt Problem 17 of the 2001 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

Which of the cones below can be formed from a 252∘252^\circ sector of a circle of radius 1010 by aligning the two straight sides?
Answer: C
Concepts:conesectorcircumference
Small hint:
The sector’s radius becomes the slant height of the cone
Big hint:
The arc length 252360⋅2π⋅10\dfrac{252}{360}\cdot2\pi\cdot10 becomes the base circumference 2πr2\pi r
Solution:
When rolled into a cone, the sector’s radius 1010 becomes the slant height, and the arc length becomes the base circumference.
The arc length is 252360⋅2π⋅10=14π,\dfrac{252}{360}\cdot2\pi\cdot10=14\pi, so 2πr=14π2\pi r=14\pi gives base radius r=7.r=7. The cone has slant height 1010 and base radius 7.7.
Thus, the correct answer is C.
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