2000 AMC 10 Problem 3

Attempt Problem 3 of the 2000 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Each day, Jenny ate 20%20\% of the jellybeans that were in her jar at the beginning of that day. At the end of the second day, 3232 remained. How many jellybeans were in the jar originally?
4040
5050
5555
6060
7575
Answer: B
Concepts:percentagework backwards
Small hint:
Eating 20%20\% leaves 80%80\% of the jellybeans at the end of each day
Big hint:
If xx is the original amount, then (0.8)2x=32(0.8)^2 x = 32
Solution:
Since Jenny eats 20%20\% each day, 80%80\% remain at the end of each day.
If xx is the original number, then (0.8)2x=0.64x=32,(0.8)^2 x = 0.64x = 32, so x=50.x = 50.
Thus, the correct answer is B.
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