2000 AMC 10 Problem 14

Attempt Problem 14 of the 2000 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 10 solutions, or check the answer key.

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14.

Mrs. Walter gave an exam in a mathematics class of five students. She entered the scores in random order into a spreadsheet, which recalculated the class average after each score was entered. Mrs. Walter noticed that after each score was entered, the average was always an integer. The scores (listed in ascending order) were 71,76,80,82,71, 76, 80, 82, and 91.91. What was the last score Mrs. Walter entered?

7171

7676

8080

8282

9191

Answer: C
Concepts:divisibilitymodular arithmeticmean
Difficulty rating: 1560
Solution:

The residues of 71,76,80,82,9171, 76, 80, 82, 91 modulo 33 are 2,1,2,1,1.2, 1, 2, 1, 1. The sum of the first three scores must be divisible by 3,3, and the only such triple is 76+82+91=249,76 + 82 + 91 = 249, so the third score entered is 9191 and the first two are 7676 and 82.82.

Since 249249 is one more than a multiple of 4,4, the fourth score must be three more than a multiple of 4,4, which only 7171 satisfies. That leaves 8080 as the fifth and last score.

Indeed 76,158,249,320,40076, 158, 249, 320, 400 are divisible by 1,2,3,4,5.1, 2, 3, 4, 5.

Thus, the correct answer is C.

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