1988 AIME Problem 6

Attempt Problem 6 of the 1988 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AIME solutions, or check the answer key.

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6.

It is possible to place positive integers into the vacant twenty-one squares of the 5×55\times5 square shown below so that the numbers in each row and column form arithmetic sequences. Find the number that must occupy the vacant square marked by the asterisk ().(*).

Answer: 142
Concepts:arithmetic sequencepattern recognitionsystem of equations
Difficulty rating: 2030
Small Hint:

Index the rows and columns from 00 through 44

Big Hint:

A grid whose rows and columns are arithmetic has the form A+Bi+Cj+DijA+Bi+Cj+Dij

Solution:

Index rows and columns from 00 to 4.4. The row and column conditions give the general entry A+Bi+Cj+Dij.A+Bi+Cj+Dij. The four shown values yield A+4B=0,A+B+C+D=74,A+2B+4C+8D=186,A+3B+2C+6D=103.\begin{aligned}A+4B&=0,\\A+B+C+D&=74,\\A+2B+4C+8D&=186,\\A+3B+2C+6D&=103.\end{aligned} Solving gives A=52,A=52, B=13,B=-13, C=30,C=30, and D=5.D=5. The asterisk is at (i,j)=(0,3),(i,j)=(0,3), so its value is A+3C=52+90=142.A+3C=52+90=142.

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