2025 AMC 8 第 25 题
先试着解答 2025 AMC 8 第 25 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2025 AMC 8 解答,或核对答案。
所有题目均经美国数学协会(MAA)官方合法授权使用。
25.
Makayla 找出在一个 菱形网格中画路径的所有可能方式。每条路径从网格底部开始,到顶部结束,每一步都向东北或西北移动一个单位。她计算每条路径与网格右边界之间区域的面积。下图给出了两个例子。所有可能路径确定的这些面积之和是多少?
Makayla finds all the possible ways to draw a path in a diamond-shaped grid. Each path starts at the bottom of the grid and ends at the top, always moving one unit northeast or northwest. She computes the area of the region between each path and the right side of the grid. Two examples are shown in the figures below. What is the sum of the areas determined by all possible paths?
答案:B
视频讲解:
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文字解答:
设所求和为 。
由对称性,如果改为求每条路径与左边界之间的面积和,结果也为 。
但若把这个和与原来的答案相加,就等于对所有路径,把左侧面积与右侧面积之和全部相加。
对每一条路径,这两个面积之和正好是 。
路径数等于重排 的方式数,其中 表示向左, 表示向右。重排数是 选 ,记为 。
所以 。两边除以 ,得到 等于 即三千一百五十,选 B。
Let be the answer.
By symmetry, if the question asked for the sum of areas between each path and the left side of the grid, then the answer would be exactly the same
But if that answer is added to the original answer, that is exactly the same as the sum over all paths, of the sum of areas to the left and to the right.
For each path, that sum of areas is exactly
The number of paths is equal to the number of ways to rearrange where stands for Left and stands for Right, as the path walks up. The number of rearrangements is choose denoted
So, Dividing by we get that equals which is 3150, or choice B.
其他年份的第 25 题
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