2024 AMC 8 第 21 题

先试着解答 2024 AMC 8 第 21 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2024 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

21.

一群青蛙(称为一个军团)住在树上。青蛙在阴影中会变成绿色,在阳光下会变成黄色。最初绿色青蛙与黄色青蛙的比为 3:13 : 1。后来 33 只绿色青蛙移到阳光处,55 只黄色青蛙移到阴影处。现在比为 4:14 : 1。现在绿色青蛙和黄色青蛙的数量相差多少?
A group of frogs (called an army) is living in a tree. A frog turns green when in the shade and turns yellow when in the sun. Initially, the ratio of green to yellow frogs was 3:1.3 : 1. Then 33 green frogs moved to the sunny side and 55 yellow frogs moved to the shady side. Now the ratio is 4:1.4 : 1. What is the difference between the number of green frogs and yellow frogs now?
1010
1212
1616
2020
2424
答案:E
知识点:比与比例一次方程换元法
小提示:
设最初黄色青蛙数为 yy
Let the initial yellow count be yy
大提示:
移动后,绿色净增加 +2+2,黄色净减少 −2-2
After the moves, green changes by +2+2 and yellow changes by −2-2
视频讲解:
解答视频缩略图
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文字解答:
设最初绿色青蛙有 gg 只,黄色青蛙有 yy 只,则 g=3yg=3y。移动后有 g+5−3y+3−5=41。\dfrac{g+5-3}{y+3-5} = \dfrac{4}{1}\text{。}
把 3y3y 代入 gg,即可求出原来的黄色青蛙数 yy:3y+2y−2=4\dfrac{3y+2}{y-2} = 4 3y+2=4(y−2)=4y−83y+2 = 4(y-2) = 4y-8 y=10y = 10
因此最初黄色有 1010 只,绿色有 3×10=303 \times 10 = 30 只。移动后黄色有 10+3−5=810+3-5 = 8 只,绿色有 30+5−3=3230+5-3=32 只,差为 32−8=2432-8=24。
所以正确答案是 E。
We can let gg be the number of green frogs and yy be the number of yellow frogs. Initially, we have g=3yg=3y. Then, after some frogs moved, we have the following proportion: g+5−3y+3−5=41.\dfrac{g+5-3}{y+3-5} = \dfrac{4}{1}.
Substituting 3y3y for gg will allow us to determine the number of yellow frogs originally (yy): 3y+2y−2=4\dfrac{3y+2}{y-2} = 4 3y+2=4(y−2)=4y−83y+2 = 4(y-2) = 4y-8 y=10y = 10
Hence, there were 1010 yellow frogs and 3×10=303 \times 10 = 30 green frogs initially. After some frogs moved, we now have 10+3−5=810+3-5 = 8 yellow frogs and 30+5−3=3230+5-3=32 green frogs, giving us a difference of 32−8=2432-8=24 between the number of green and yellow frogs.
Thus, E is the correct answer.
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