2022 AMC 8 第 21 题

先试着解答 2022 AMC 8 第 21 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2022 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

21.

Steph 在一场比赛上半场投进 1515 球,共出手 2020 次;下半场投进 1010 球,共出手 1010 次。Candace 上半场出手 1212 次,下半场出手 1818 次。在每个半场中,Steph 的命中率都高于 Candace。令人惊讶的是,她们最终总命中率相同。Candace 下半场比上半场多进了多少球?
Steph scored 1515 baskets out of 2020 attempts in the first half of a game, and 1010 baskets out of 1010 attempts in the second half. Candace took 1212 attempts in the first half and 1818 attempts in the second. In each half, Steph scored a higher percentage of baskets than Candace. Surprisingly they ended with the same overall percentage of baskets scored. How many more baskets did Candace score in the second half than in the first?
77
88
99
1010
1111
答案:C
知识点:百分数不等式
小提示:
Steph 总共投进 2525 球,共出手 3030 次。
Steph made 2525 baskets in 3030 attempts overall
大提示:
Candace 也必须总共投进 2525 球。
Candace must also have made 2525 baskets total
解答:
Steph 总共进了 2525 球,出手 3030 次。Candace 也出手了 12+18=3012+18=30 次,且两人的总命中率相同,所以 Candace 也进了 2525 球。
设 Candace 上半场进 ff 球,下半场进 ss 球,则 f+s=25f+s=25。
Steph 上半场命中率为 1520=34\frac{15}{20}=\frac34,所以 f12<34\frac{f}{12}<\frac34,得到 f<9f<9。Steph 下半场命中率为 11,所以 s<18s<18。
因此 f≤8f\le8 且 s≤17s\le17。又 f+s=25f+s=25,唯一可能是 f=8f=8、s=17s=17,所以 s−f=9s-f=9。
正确答案是 C。
Steph made 2525 baskets in 3030 attempts. Candace also took 12+18=3012+18=30 attempts, and their overall percentages were the same, so Candace also made 2525 baskets.
Let ff be Candace’s first-half baskets and ss be her second-half baskets. Then f+s=25f+s=25.
Steph’s first-half percentage was 1520=34\frac{15}{20}=\frac34, so f12<34\frac{f}{12}<\frac34, giving f<9f<9. Steph’s second-half percentage was 11, so s<18s<18.
Thus f≤8f\le8 and s≤17s\le17. Since f+s=25f+s=25, the only possibility is f=8f=8 and s=17s=17, so s−f=9s-f=9.
Thus, the correct answer is C.
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