2018 AMC 8 第 23 题

先试着解答 2018 AMC 8 第 23 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2018 AMC 8 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

23.

从一个正八边形中随机选择三个顶点并连接成一个三角形。这个三角形至少有一条边也是八边形的一条边的概率是多少?

From a regular octagon, a triangle is formed by connecting three randomly chosen vertices of the octagon. What is the probability that at least one of the sides of the triangle is also a side of the octagon?

27\dfrac{2}{7}

542\dfrac{5}{42}

1114\dfrac{11}{14}

57\dfrac{5}{7}

67\dfrac{6}{7}

答案:D
知识点:补集计数隔板法
难度评级:1650
视频讲解:
解答视频缩略图
Play video

Click to load, then click again to play

文字解答:

用补集计数:计算任意两个所选顶点都不相邻的三角形。从一个所选顶点出发,设三个间隔中未选顶点的正整数个数为 x,y,zx,y,z。那么 x+y+z=5x+y+z=5,共有 (42)=6\binom42=6 个正整数解。

起点有 88 种选择,而每个三角形会从它的 33 个顶点各被计算一次,所以补集中有 86/3=168\cdot6/3=16 个三角形。全部三角形共有 (83)=56\binom83=56 个,因此所求概率是 116/56=5/71-16/56=5/7

所以正确答案是 D

Count the complement: triangles with no two chosen vertices adjacent. Starting at a chosen vertex, let x,y,zx,y,z be the positive numbers of unchosen vertices in the three gaps. Then x+y+z=5x+y+z=5, which has (42)=6\binom42=6 positive solutions.

There are 88 choices for the starting vertex, and each triangle is counted from each of its 33 vertices, so the complement contains 86/3=168\cdot6/3=16 triangles. Out of (83)=56\binom83=56 total triangles, the desired probability is 116/56=5/7.1-16/56=5/7.

Thus, D is the correct answer.

← 第 22 题#22
完整试卷

其他年份的第 23 题

1985 AMC 8 · 1986 AMC 8 · 1987 AMC 8 · 1988 AMC 8 · 1989 AMC 8 · 1990 AMC 8 · 1991 AMC 8 · 1992 AMC 8 · 1993 AMC 8 · 1994 AMC 8 · 1995 AMC 8 · 1996 AMC 8 · 1997 AMC 8 · 1998 AMC 8 · 1999 AMC 8 · 2000 AMC 8 · 2001 AMC 8 · 2002 AMC 8 · 2003 AMC 8 · 2004 AMC 8 · 2005 AMC 8 · 2006 AMC 8 · 2007 AMC 8 · 2008 AMC 8 · 2009 AMC 8 · 2010 AMC 8 · 2011 AMC 8 · 2012 AMC 8 · 2013 AMC 8 · 2014 AMC 8 · 2015 AMC 8 · 2016 AMC 8 · 2017 AMC 8 · 2019 AMC 8 · 2020 AMC 8 · 2022 AMC 8 · 2023 AMC 8 · 2024 AMC 8 · 2025 AMC 8 · 2026 AMC 8