Question

Barry 写了 $6$ 个不同的数，分别写在 $3$ 张卡片的两面，并把卡片如图摆在桌上。每张卡片两面数字之和都相等。三个隐藏面上的数都是质数。隐藏的质数的平均数是多少？

Barry wrote $6$ different numbers, one on each side of $3$ cards, and laid the cards on a table, as shown. The sums of the two numbers on each of the three cards are equal. The three numbers on the hidden sides are prime numbers. What is the average of the hidden prime numbers?

$13$

$14$

$15$

$16$

$17$

答案：B

知识点：质数奇偶性平均数

难度评级：1650

解答：

公共和必须是奇数。如果公共和是偶数，那么 $44$ 和 $38$ 背后的隐藏数都必须是偶质数，但偶质数只有一个。

所以奇数 $59$ 背后的隐藏质数必须是 $2$ ，公共和为 $59+2=61$ 。

另外两个隐藏质数是 $61-44=17$ 和 $61-38=23$ 。

隐藏质数的平均数为 $\dfrac{2+17+23}{3}=14$ 。

所以正确答案是 B。

The common sum must be odd. If the common sum were even, then the hidden numbers behind $44$ and $38$ would both have to be even primes, but there is only one even prime.

So the prime hidden behind the odd visible number $59$ must be $2$ , making the common sum $59+2=61$ .

The other two hidden primes are $61-44=17$ and $61-38=23$ .

The average of the hidden primes is $\dfrac{2+17+23}{3}=14$ .

Thus, B is the correct answer.

2006 AMC 8 第 25 题

答案：B

难度评级：1650

解答：

其他年份的第 25 题