Question

一个水族箱的长方形底面为 $100$ cm 乘 $40$ cm，高 $50$ cm。水族箱中水深 $37$ cm。随后放入一个体积为 $1000\text{ cm}^3$ 的石头并完全浸没。水位上升多少厘米？

An aquarium has a rectangular base that measures $100$ cm by $40$ cm and has a height of $50$ cm. The aquarium is filled with water to a depth of $37$ cm. A rock with volume $1000\text{ cm}^3$ is then placed in the aquarium and completely submerged. By how many centimeters does the water level rise?

$0.25$

$0.5$

$1$

$1.25$

$2.5$

答案：A

知识点：体积长方体

难度评级：1310

解答：

水族箱底面积为 $100\cdot 40=4000\text{ cm}^2$ 。

完全浸没的石头排开 $1000\text{ cm}^3$ 的水，所以水位上升 $1000\div 4000=0.25$ cm。

所以正确答案是 A。

The base area of the aquarium is $100\cdot 40=4000\text{ cm}^2$ .

The submerged rock displaces $1000\text{ cm}^3$ of water, so the water level rises by $1000\div 4000=0.25$ cm.

Thus, A is the correct answer.

2006 AMC 8 第 21 题

答案：A

难度评级：1310

解答：

其他年份的第 21 题