1999 AMC 8 第 12 题

先试着解答 1999 AMC 8 第 12 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1999 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

12.

中学小将队赢的场数与输的场数之比为 114\frac{11}{4},没有平局。四舍五入到最接近的整数百分比,这支队输了百分之多少的比赛?
The ratio of the number of games won to the number of games lost (no ties) by the Middle School Middies is 114.\frac{11}{4}. To the nearest whole percent, what percent of its games did the team lose?
24%24\%
27%27\%
36%36\%
45%45\%
73%73\%
答案:B
知识点:比与比例百分数
小提示:
把 1111 胜 44 负看作一组
Use 1111 wins and 44 losses as one batch
大提示:
输掉的比例是输的场数除以总场数
The lost fraction is losses over total games
解答:
可以把这支队看成每 1515 场比赛中赢 1111 场、输 44 场。
输掉的百分比为 415⋅100%≈27%\dfrac4{15}\cdot100\%\approx 27\%。
所以正确答案是 B。
The team can be viewed as winning 1111 games and losing 44 games in each batch of 1515 games.
The percent lost is 415⋅100%≈27%\dfrac4{15}\cdot100\%\approx 27\%.
Thus, B is the correct answer.
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