1997 AMC 8 第 12 题

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12.

已知 求 4\angle 41+2=180\angle 1 + \angle 2 = 180^\circ 3=4\angle 3 = \angle 4

1+2=180\angle 1 + \angle 2 = 180^\circ 3=4\angle 3 = \angle 4 Find 4\angle 4

2020^\circ

2525^\circ

3030^\circ

3535^\circ

4040^\circ

答案:D
知识点:导角角度和
难度评级:1170
解答:

由三角形内角和,因为三角形内角和为 180180^{\circ}1=1807040=70 \angle 1 = 180^{\circ} - 70^{\circ} - 40^{\circ} = 70^{\circ}

因为 1\angle 12\angle 2 互补,所以 。 2=1801=110 \angle 2 = 180^{\circ} - \angle 1 = 110^{\circ}

最后, 3+4+110=180 \angle 3 + \angle 4 + 110^{\circ} = 180^{\circ} \Rightarrow 24=704=35. 2 \angle 4 = 70^{\circ} \Rightarrow \angle 4 = 35^{\circ}.

所以正确答案是 D

We have that 1=1807040=70 \angle 1 = 180^{\circ} - 70^{\circ} - 40^{\circ} = 70^{\circ} using the fact that the interior angles of a triangle add to 180.180^{\circ}.

This tells us that 2=1801=110 \angle 2 = 180^{\circ} - \angle 1 = 110^{\circ} since 1\angle 1 and 2\angle 2 are supplementary.

Finally, 3+4+110=180 \angle 3 + \angle 4 + 110^{\circ} = 180^{\circ} \Rightarrow24=704=35. 2 \angle 4 = 70^{\circ} \Rightarrow \angle 4 = 35^{\circ}.

Thus, D is the correct answer.

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