1991 AMC 8 第 25 题

先试着解答 1991 AMC 8 第 25 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1991 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

25.

一个等边三角形最初被涂成黑色。每次改变时,每个黑色三角形的中间四分之一变成白色。经过五次改变后,仍为黑色的部分占原三角形面积的几分之几?
An equilateral triangle is originally painted black. Each time the triangle is changed, the middle fourth of each black triangle turns white. After five changes, what fractional part of the original area of the black triangle remains black?
11024\dfrac{1}{1024}
1564\dfrac{15}{64}
2431024\dfrac{243}{1024}
14\dfrac14
81256\dfrac{81}{256}
答案:C
知识点:等比数列面积比
小提示:
改变一次后,中间四分之一变白,所以黑色面积剩下 34\dfrac34
After one change the middle fourth turns white, so 34\dfrac34 of the black area remains
大提示:
每次改变都会把黑色面积乘以 34\dfrac34,所以五次后乘以 (34)5\left(\dfrac34\right)^5
Each change multiplies the black area by 34,\dfrac34, so after five changes multiply by (34)5\left(\dfrac34\right)^5
解答:
每一次改变都会让当前黑色面积的 34\dfrac34 保持黑色。五次改变后,黑色面积比例为 (34)5=2431024。\left(\dfrac34\right)^5 = \dfrac{243}{1024}\text{。}
所以正确答案是 C。
Each change leaves 34\dfrac34 of the current black area black. After five changes the black fraction is (34)5=2431024.\left(\dfrac34\right)^5 = \dfrac{243}{1024}.
Thus, the correct answer is C .
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