1989 AMC 8 第 21 题

先试着解答 1989 AMC 8 第 21 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1989 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

21.

杰克有一袋 128128 个苹果。他先把其中的 25%25\% 卖给吉尔。接着,他又把袋中剩余苹果的 25%25\% 卖给琼。之后,他把袋中剩下的苹果中最亮的一个送给了老师。最后袋中还剩多少个苹果?
Jack had a bag of 128128 apples. He sold 25%25\% of them to Jill. Next he sold 25%25\% of those remaining to June. Of those apples still in his bag, he gave the shiniest one to his teacher. How many apples did Jack have then?
77
6363
6565
7171
111111
答案:D
知识点:百分数
小提示:
卖掉 25%25\% 后会剩下 75%=3475\% = \frac{3}{4}
Selling 25%25\% leaves 75%=3475\% = \frac{3}{4} of the apples
大提示:
把 128128 连续乘以 34\frac{3}{4} 两次,然后再减去送给老师的那个苹果
Multiply 128128 by 34\frac{3}{4} twice, then subtract the one given to the teacher
解答:
杰克第一次卖掉 25%25\% 后,剩下 34×128=96\frac{3}{4} \times 128 = 96 个苹果。第二次又卖掉余数的 25%25\%,剩下 34×96=72\frac{3}{4} \times 96 = 72 个苹果。
再送给老师 11 个后,剩下 72−1=7172 - 1 = 71 个。
所以正确答案是 D。
After selling 25%25\% to Jill, Jack keeps 34×128=96\frac{3}{4} \times 128 = 96 apples. After selling 25%25\% of those to June, he keeps 34×96=72\frac{3}{4} \times 96 = 72 apples.
He then gives 11 to his teacher, leaving 72−1=71.72 - 1 = 71.
Thus, the correct answer is D .
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