Question

七点整时，时针和分针之间较小的夹角是多少？

How many degrees are in the smaller angle between the hour hand and the minute hand of a clock that reads seven o'clock?

$50^\circ$

$120^\circ$

$135^\circ$

$150^\circ$

$165^\circ$

知识点：时钟

钟面上的 $12$ 个数字把一周分成 $12$ 等份，每份是 $\frac{360^\circ}{12} = 30^\circ$ 。

七点整时，分针指向 $12$ ，时针指向 $7$ 。沿较短方向相隔 $5$ 个刻度，所以角度是 $5 \times 30^\circ = 150^\circ$ 。

所以正确答案是 D。

The $12$ numbers divide the clock into $12$ equal sections of $\frac{360^\circ}{12} = 30^\circ$ each.

At seven o'clock the hands point to $12$ and $7,$ which are $5$ sections apart the short way, giving $5 \times 30^\circ = 150^\circ.$

Thus, the correct answer is D .