1987 AMC 8 第 25 题

先试着解答 1987 AMC 8 第 25 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1987 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

25.

罐子里有编号 11 到 1010 的十个球。杰克伸手随机取出一个球。然后吉尔伸手随机取出另一个不同的球。取出的两个球上的数字之和为偶数的概率是多少?
Ten balls numbered 11 to 1010 are in a jar. Jack reaches into the jar and randomly removes one of the balls. Then Jill reaches into the jar and randomly removes a different ball. What is the probability that the sum of the two numbers on the balls removed is even?
49\dfrac{4}{9}
919\dfrac{9}{19}
12\dfrac{1}{2}
1019\dfrac{10}{19}
59\dfrac{5}{9}
答案:A
知识点:基本概率奇偶性
小提示:
两个数的和为偶数,当且仅当两个数同为奇数或同为偶数
The sum of two numbers is even exactly when both are odd or both are even
大提示:
有 55 个奇数球和 55 个偶数球;在全部 (102)\binom{10}{2} 对中数出同奇偶性的对数
There are 55 odd and 55 even balls; count the matching-parity pairs out of all (102)\binom{10}{2} pairs
解答:
和为偶数时,两个球同为奇数或同为偶数。全奇的配对有 (52)=10\binom{5}{2} = 10 对,全偶的配对也有 (52)=10\binom{5}{2} = 10 对,共 2020 对有利情况。
总配对数是 (102)=45\binom{10}{2} = 45,所以概率是 2045=49\dfrac{20}{45} = \dfrac49。
所以正确答案是 A。
The sum is even when both balls are odd or both are even. There are (52)=10\binom{5}{2} = 10 all-odd pairs and (52)=10\binom{5}{2} = 10 all-even pairs, for 2020 favorable pairs.
The total number of pairs is (102)=45,\binom{10}{2} = 45, so the probability is 2045=49.\dfrac{20}{45} = \dfrac49.
Thus, the correct answer is A .
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