1987 AMC 8 第 25 题

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25.

罐子里有编号 111010 的十个球。Jack 伸手随机取出一个球。然后 Jill 伸手随机取出另一个不同的球。取出的两个球上的数字之和为偶数的概率是多少?

Ten balls numbered 11 to 1010 are in a jar. Jack reaches into the jar and randomly removes one of the balls. Then Jill reaches into the jar and randomly removes a different ball. What is the probability that the sum of the two numbers on the balls removed is even?

49\dfrac{4}{9}

919\dfrac{9}{19}

12\dfrac{1}{2}

1019\dfrac{10}{19}

59\dfrac{5}{9}

答案:A
知识点:基本概率奇偶性
难度评级:1090
解答:

和为偶数时,两个球同为奇数或同为偶数。全奇的配对有 (52)=10\binom{5}{2} = 10 对,全偶的配对也有 (52)=10\binom{5}{2} = 10 对,共 2020 对有利情况。

总配对数是 (102)=45\binom{10}{2} = 45,所以概率是 2045=49\dfrac{20}{45} = \dfrac49

所以正确答案是 A

The sum is even when both balls are odd or both are even. There are (52)=10\binom{5}{2} = 10 all-odd pairs and (52)=10\binom{5}{2} = 10 all-even pairs, for 2020 favorable pairs.

The total number of pairs is (102)=45,\binom{10}{2} = 45, so the probability is 2045=49.\dfrac{20}{45} = \dfrac49.

Thus, the correct answer is A .

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