2025 AMC 8 Problem 20

Attempt Problem 20 of the 2025 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

Sarika, Dev, and Rajiv are sharing a large block of cheese. They take turns cutting off half of what remains and eating it: first Sarika eats half of the cheese, then Dev eats half of the remaining half, then Rajiv eats half of what remains, then back to Sarika, and so on. They stop when the cheese is too small to see. About what fraction of the original block of cheese does Sarika eat in total?
47\dfrac{4}{7}
35\dfrac{3}{5}
23\dfrac{2}{3}
34\dfrac{3}{4}
78\dfrac{7}{8}
Answer: A
Concepts:geometric sequencesummation
Small hint:
Sarika eats every third term of the halving sequence
Big hint:
Her shares form a geometric series with ratio 18\frac{1}{8}
Video solution:
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Written solution:
Sarika gets 12\frac{1}{2} of the cheese in the first step.
Then Dev gets 122\frac{1}{2^2} of the cheese.
Then Rajiv gets 123\frac{1}{2^3} of the cheese.
Sarika then gets another 124\frac{1}{2^4} of the cheese.
This pattern continues. Ultimately, Sarika gets 12+124+127+… \frac{1}{2} + \frac{1}{2^4} + \frac{1}{2^7} + \dots which is the sum of an infinite geometric series with first term a=12a = \frac{1}{2} and common ratio r=123.r = \frac{1}{2^3}. That sum is a1−r=121−18=1278=47 \frac{a}{1-r} = \frac{\frac{1}{2}}{1 - \frac{1}{8}} = \frac{\frac{1}{2}}{\frac{7}{8}} = \frac{4}{7} which is choice A.
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