2022 AMC 8 Problem 24

Attempt Problem 24 of the 2022 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 8 solutions, or check the answer key.

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24.

The figure below shows a polygon ABCDEFGH,ABCDEFGH, consisting of rectangles and right triangles. When cut out and folded on the dotted lines, the polygon forms a triangular prism. Suppose that:

AH=EF=8 AH = EF = 8

and

GH=14. GH = 14.

What is the volume of the prism?

112112

128128

192192

240240

288288

Answer: C
Concepts:net (3D geometry)volume
Difficulty rating: 1510
Solution:

When the net is folded, the matching side lengths give GF=EF=8GF=EF=8. Since GFCBGFCB is a rectangle, BC=8BC=8. The fold identifies ABAB with BCBC, so AB=8AB=8. In rectangle HJBAHJBA, this gives HJ=8HJ=8, and the opposite side BJBJ equals AH=8AH=8.

Since GH=14GH=14, we have GJ=148=6GJ=14-8=6. Thus one triangular base of the prism is right triangle BJGBJG, with area 682=24. \frac{6\cdot8}{2}=24. The prism length is GF=8GF=8, so the volume is 248=19224\cdot8=192.

Thus, the correct answer is C.

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