2019 AMC 8 Problem 18

Attempt Problem 18 of the 2019 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

The faces of each of two fair dice are numbered 1,1, 2,2, 3,3, 5,5, 7,7, and 8.8. When the two dice are tossed, what is the probability that their sum will be an even number?
49\displaystyle \dfrac{4}{9}
12\displaystyle \dfrac{1}{2}
59\displaystyle \dfrac{5}{9}
35\displaystyle \dfrac{3}{5}
23\displaystyle \dfrac{2}{3}
Answer: C
Concepts:dice (probability)parity
Small hint:
An even sum means both dice have the same parity
Big hint:
Each die has 22 even faces and 44 odd faces
Video solution:
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Written solution:
The only two ways that the sum can be even is if both rolls are even or both are odd.
The probability that a roll is even is 26=13,\dfrac{2}{6} = \dfrac{1}{3}, and the probability that it is odd is 46=23.\dfrac{4}{6} = \dfrac{2}{3}.
Therefore, the desired probability is 13⋅13+23⋅23=59. \dfrac{1}{3} \cdot \dfrac{1}{3} + \dfrac{2}{3} \cdot \dfrac{2}{3} = \dfrac{5}{9}.
Thus, the correct answer is C.
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