2018 AMC 8 Problem 18

Attempt Problem 18 of the 2018 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

How many positive factors does 23,23223{,}232 have?
9 9
12 12
28 28
36 36
42 42
Answer: E
Concepts:prime factorizationfactor counting
Small hint:
Prime-factorize 23,23223,232.
Big hint:
If n=paqbrcn=p^a q^b r^c, then its number of positive factors is (a+1)(b+1)(c+1)(a+1)(b+1)(c+1).
Video solution:
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Written solution:
The prime factorization is 23,232=26⋅3⋅112.23{,}232=2^6\cdot3\cdot11^2. A divisor may use any exponent from 00 through 66 on 22, from 00 through 11 on 33, and from 00 through 22 on 1111. Therefore, the number of positive divisors is (6+1)(1+1)(2+1)=42.(6+1)(1+1)(2+1)=42.
Thus, E is the correct answer.
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