2016 AMC 8 Problem 2

Attempt Problem 2 of the 2016 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

In rectangle $ABCD,$ $AB=6$ and $AD=8.$ Point $M$ is the midpoint of $\overline{AD}.$ What is the area of $\triangle AMC?$

$12$

$15$

$18$

$20$

$24$

Answer: A

Concepts:triangle area midpoint

Difficulty rating: 450

Video solution:

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Written solution:

From the diagram, we can see that the base of $\triangle AMC$ is $4$ and the altitude is $6.$ The area is therefore $\dfrac{1}{2} \cdot 4 \cdot 6 = 12.$

Thus, A is the correct answer.

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