2016 AMC 8 Problem 19

Attempt Problem 19 of the 2016 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

The sum of 2525 consecutive even integers is 10,000.10{,}000. What is the largest of these 2525 consecutive even integers?
360 360
388 388
412 412
416 416
424 424
Answer: E
Concepts:arithmetic sequence
Small hint:
For an odd number of consecutive terms, the average is the middle term.
Big hint:
There are 1212 even integers larger than the middle term.
Video solution:
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Written solution:
The average of these numbers is 10,00025=400.\frac{10{,}000}{25} = 400. The largest number is 1212 even numbers away, which means that it equals 400+12⋅2=424.400 + 12 \cdot 2 = 424.
Thus, E is the correct answer.
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