2015 AMC 8 Problem 19

Attempt Problem 19 of the 2015 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 8 solutions, or check the answer key.

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19.

A triangle with vertices at A=(1,3),A=(1,3), B=(5,1),B=(5,1), and C=(4,4)C=(4,4) is plotted on a 6×56\times5 grid. What fraction of the grid is covered by the triangle?

16 \dfrac{1}{6}

15 \dfrac{1}{5}

14 \dfrac{1}{4}

13 \dfrac{1}{3}

12 \dfrac{1}{2}

Answer: A
Concepts:coordinate geometrytriangle area
Difficulty rating: 1320
Video solution:
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Written solution:

The total area of the grid is 65=30.6\cdot5=30. To find the area of the triangle, place it inside the 44-by-33 rectangle shown below.

The rectangle has area 43=12.4\cdot3=12. The three corner triangles have areas 12(4)(2)=4,\dfrac12(4)(2)=4, 12(1)(3)=32,\dfrac12(1)(3)=\dfrac32, and 12(3)(1)=32.\dfrac12(3)(1)=\dfrac32. Therefore, [ABC]=1243232=5.\begin{aligned} [\triangle ABC] &= 12-4-\dfrac32-\dfrac32\\ &=5. \end{aligned}

Therefore, the fraction of the area is 530=16.\dfrac{5}{30} = \dfrac{1}{6} .

Thus, the correct answer is A .

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