2013 AMC 8 Problem 15

Attempt Problem 15 of the 2013 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

If 3p+34=903^p + 3^4 = 90, 2r+44=762^r + 44 = 76, and 53+6s=14215^3 + 6^s = 1421, what is the product of pp, rr, and ss?
2727
4040
5050
7070
9090
Answer: B
Concepts:exponent
Small hint:
Subtract the known number from each equation.
Big hint:
Identify 3p3^p, 2r2^r, and 6s6^s as familiar powers.
Video solution:
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Written solution:
Subtract the known number from each equation: 3p=90−81=9,3^p=90-81=9, 2r=76−44=32,2^r=76-44=32, 6s=1421−125=1296.6^s=1421-125=1296.
Therefore p=2p=2, r=5r=5, and s=4s=4. Their product is 2⋅5⋅4=402\cdot5\cdot4=40.
Thus, B is the correct answer.
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