2012 AMC 8 Problem 16

Attempt Problem 16 of the 2012 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

Each of the digits 0,0, 1,1, 2,2, 3,3, 4,4, 5,5, 6,6, 7,7, 8,8, and 99 is used only once to make two five-digit numbers so that they have the largest possible sum. Which of the following could be one of the numbers?
76531 76531
86724 86724
87431 87431
96240 96240
97403 97403
Answer: C
Concepts:place valueoptimization
Small hint:
Put the largest digits in the largest place values.
Big hint:
The ten-thousands digits should be 99 and 88, then continue in pairs.
Video solution:
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Written solution:
To construct two five-digit numbers, the digits in the largest place values must be as great as possible. Therefore, the leftmost digits must be the greatest two digits. This means the first digit must be either 99 or 8,8, the second digit must be either 77 or 6,6, the third digit must be either 55 or 4,4, the fourth digit must be either 33 or 2,2, and the last digit must be either 11 or 0.0.
The only one of the given numbers that satisfy this is 87431.87431.
Thus, the answer is C .
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