2010 AMC 8 Problem 18

Attempt Problem 18 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

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18.

A decorative window is made up of a rectangle with semicircles on either end. The ratio of ADAD to ABAB is 3:2,3:2, and AB=30AB=30 inches. What is the ratio of the area of the rectangle to the combined areas of the semicircles?

 2:3 \ 2:3

 3:2 \ 3:2

 6:π \ 6:\pi

 9:π \ 9:\pi

 30:π \ 30 :\pi

Answer: C
Concepts:circle arearectanglearea ratio
Difficulty rating: 1240
Solution:

Combining the semicircles would make a circle of diameter d=30.d=30. This would make the radius equal to d2. \dfrac{d}{2}. Therefore, the combined area of the semicircles is (d2)2π=πd24.(\dfrac{d}{2})^2 \cdot \pi = \dfrac{\pi d^2}{4}.

Side AD=32dAD = \dfrac 32 d because AD:AB=3:2AD:AB=3:2 and AB=d.AB=d. The area of the rectangle is therefore 32d2. \dfrac 32 d^2. The ratio of the area of the rectangle to the area of the semicircles is 32d2πd24=6π.\dfrac{\dfrac 32 d^2}{\dfrac{\pi d^2}{4}} = \dfrac{6}{\pi}.

Thus, the answer is C .

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