2010 AMC 8 Problem 16

Attempt Problem 16 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

A square and a circle have the same area. What is the ratio of the side length of the square to the radius of the circle?
 π2 \ \dfrac{\sqrt{\pi}}{2}
 π \ \sqrt{\pi}
 π \ \pi
 2π \ 2\pi
 π2 \ \pi^{2}
Answer: B
Concepts:circle areasquare (geometry)
Small hint:
Set s2=πr2s^2=\pi r^2 and solve for sr\frac{s}{r}.
Big hint:
Write the square area and circle area in terms of side length and radius.
Solution:
Let ss be the side length of the square and let rr be the radius of the circle. Then, since they have the same areas, s2=πr2.s^2 = \pi r^2 . This means (sr)2=π,(\dfrac sr)^2 = \pi, so sr=π.\frac sr = \sqrt{ \pi} .
Thus, the answer is B .
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