2009 AMC 8 Problem 18

Attempt Problem 18 of the 2009 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

The diagram represents a 77-foot-by-77-foot floor that is tiled with 11-square-foot shaded tiles and unshaded tiles. Notice that the corners have unshaded tiles. If a 1515-foot-by-1515-foot floor is to be tiled in the same manner, how many unshaded tiles will be needed?

4949

5757

6464

9696

126126

Answer: C
Concepts:pattern recognitionperfect square
Difficulty rating: 1310
Solution:

In the 7×77\times7 example, there are 44 rows that contain 44 unshaded tiles, for 42=164^2=16 unshaded tiles.

For a 15×1515\times15 floor with the same pattern, there will be 88 such rows with 88 unshaded tiles each.

Thus the number of unshaded tiles is 82=648^2=64.

Thus, C is the correct answer.

← Problem 17#17
Full Exam

Problem 18 in Other Years

1985 AMC 8 · 1986 AMC 8 · 1987 AMC 8 · 1988 AMC 8 · 1989 AMC 8 · 1990 AMC 8 · 1991 AMC 8 · 1992 AMC 8 · 1993 AMC 8 · 1994 AMC 8 · 1995 AMC 8 · 1996 AMC 8 · 1997 AMC 8 · 1998 AMC 8 · 1999 AMC 8 · 2000 AMC 8 · 2001 AMC 8 · 2002 AMC 8 · 2003 AMC 8 · 2004 AMC 8 · 2005 AMC 8 · 2006 AMC 8 · 2007 AMC 8 · 2008 AMC 8 · 2010 AMC 8 · 2011 AMC 8 · 2012 AMC 8 · 2013 AMC 8 · 2014 AMC 8 · 2015 AMC 8 · 2016 AMC 8 · 2017 AMC 8 · 2018 AMC 8 · 2019 AMC 8 · 2020 AMC 8 · 2022 AMC 8 · 2023 AMC 8 · 2024 AMC 8 · 2025 AMC 8 · 2026 AMC 8