2004 AMC 8 Problem 4
Attempt Problem 4 of the 2004 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
4.
Ms. Hamilton’s eighth-grade class wants to participate in the annual three-person-team basketball tournament. Lance, Sally, Joy, and Fred are chosen for the team. In how many ways can the three starters be chosen?
Answer: B
Small hint:
Choosing the three starters is the same as choosing who sits out.
Big hint:
There are possible players who could be the alternate.
Solution:
If there are starters, then one person must not be starting. Choosing the person who doesn’t start determines the starters.
There are choices for the person who doesn’t start.
Thus, B is the correct answer.
Problem 4 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
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- 1989 AMC 8
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