1993 AMC 8 Problem 4 — Solution | LIVE by Po-Shen Loh

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1993 AMC 8 Problem 4

Attempt Problem 4 of the 1993 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

$1000 \times 1993 \times 0.1993 \times 10 =$

$1.993 \times 10^3$

$1993.1993$

$(199.3)^2$

$1{,}993{,}001.993$

$(1993)^2$

Answer: E

Concepts:place value exponent

Difficulty rating: 730

Solution:

Regroup as $(1000 \times 10)$ $\times 0.1993$ $\times 1993$ $= 10000$ $\times 0.1993$ $\times 1993.$

Since $10000 \times 0.1993 = 1993,$ the product is $1993 \times 1993 = (1993)^2.$

Thus, the correct answer is E .

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Problem 4 in Other Years

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