2002 AMC 8 Problem 23

Attempt Problem 23 of the 2002 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

A corner of a tiled floor is shown. If the entire floor is tiled in this way and each of the four corners looks like this one, then what fraction of the tiled floor is made of darker tiles?
13\dfrac{1}3
49\dfrac{4}9
12\dfrac{1}2
59\dfrac{5}9
58\dfrac{5}8
Answer: B
Concepts:tilingarea ratio
Small hint:
Look for a repeating 3×33\times3 block.
Big hint:
In one block, combine pairs of half dark squares into whole dark squares.
Solution:
Notice that there are repeating 3×33 \times 3 regions with the same pattern (they might be rotated differently).
In this region, there are three dark unit squares and two dark triangles that combine to form another unit square.
This makes the area of the darker region 44 and the whole region 9.9. The desired fraction is then 49.\dfrac{4}{9}.
Thus, B is the correct answer.
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