1997 AMC 8 Problem 1

Attempt Problem 1 of the 1997 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1997 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

110+9100+91000+710000= \dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000} =
0.00260.0026
0.01970.0197
0.19970.1997
0.260.26
1.9971.997
Answer: C
Concepts:decimalplace value
Small hint:
Add the tenths, hundredths, thousandths, and ten-thousandths digits
Big hint:
Convert each fraction to its decimal place value
Solution:
Converting all the fractions to decimals, we get 0.1+0.09+0.009+0.0007=0.1997. \begin{aligned} 0.1 + 0.09 + 0.009 &+ 0.0007 \\ &= 0.1997. \end{aligned}
Thus, C is the correct answer.
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