1996 AMC 8 Problem 15

Attempt Problem 15 of the 1996 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1996 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

The remainder when the product 1492⋅1776⋅1812⋅19961492 \cdot 1776 \cdot 1812 \cdot 1996 is divided by 55 is
00
11
22
33
44
Answer: E
Concepts:units digitmodular arithmetic
Small hint:
The remainder upon division by 55 depends only on the units digit of the product
Big hint:
Multiply the units digits 2,2, 6,6, 2,2, and 66 and look at that product’s units digit
Solution:
The units digit of the product equals the units digit of 2⋅6⋅2⋅6=144,2 \cdot 6 \cdot 2 \cdot 6 = 144, which is 4.4.
A number ending in 4,4, when divided by 5,5, leaves remainder 4.4.
Thus, the correct answer is E .
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